Given the diameter of the circle as input, print its area.
For pi use 22/7 instead of 3.14 or Math.pi.
Also Area=(22*radius*radius)/7
Input Format
For each test case, you will get diameter as an integer input.
Constraints
1<= diameter <= 2^31-1
Output Format
Print the output in the integer format.
Sample Input 0
8
Sample Output 0
50
Explanation 0
8 is the diameter of the circle, so 4 is the radius. So area is 50.2857, but since we have to print an integer so we print 50.
import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;
public class Solution {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int diameter =sc.nextInt();
//we know radius of circle is always half of the diameter
int radius = diameter/2;
int area=(22*radius*radius)/7;
System.out.print(area);
}
}
